Laws of indices
Before discussing about the laws of indices, we will discuss about base, index and root.
Base and index:
If m is an integer,
aᵐ = a×a×a×...×a(m times).
Here, ''a" is called base and "m" is called index of "a".
That is, in aᵐ , the number "a" itself is called base and how many times we multiply it is called it's index or power.
That is, in aᵐ , the number "a" itself is called base and how many times we multiply it is called it's index or power.
As for example,
2⁵= 2×2×2×2×2
(-3)⁵= (-3)(-3)(-3)(-3)(-3)
x⁴= x×x×x×x
Here, 2, -3, x are called base and 4,5 are index.
Root:
If a and x be two real numbers and n be any positive integer such that, aⁿ=x , then, a is called as n-th root of x and denoted by , ⁿ√x or (x)ˡ/ⁿ.
In particular, if n=2,3 then a is called as the square and cube roots of x respectively.
example, Let, a²= 64, a=?
Here, we have, 64=8².
Now, a² = 8²
or, a=+8 or -8.
Here 8 is the square root of 64.
example, Let, a²= 64, a=?
Here, we have, 64=8².
Now, a² = 8²
or, a=+8 or -8.
Here 8 is the square root of 64.
Note:
For, square root of a number 25(say) , we have two results +5 and-5.
For, cube root of a number, one and only one is positive.
In general, for n-th root of a number one and only one positive root.
Laws of indices
(1) (aᵐ)×(aⁿ)=aᵐ⁺ⁿ
(2) (aᵐ)÷(aⁿ)=aᵐ⁻ⁿ
(3) (aᵐ)ⁿ= aᵐⁿ
(4) (ab)ᵐ= (aᵐ)×(bᵐ)
(5)(a÷b)ᵐ= (aᵐ)÷(bᵐ)
(6) If m is a positive number, a⁻ᵐ=1÷(aᵐ). Here, a⁻ᵐ is called reciprocal of aᵐ.
(7) If m,n are integer, aᵐ/ⁿ means (aᵐ)ˡ/ⁿ ; i.e., n-th root of aᵐ.
(8) If m=0, a⁰ is meaningless, a⁰=1.
(9) If a,m,n real and aᵐ=aⁿ then, m=n, where, a not equal to 0,1,-1.
(10) If a, b, m are real , and aᵐ= bᵐ then, either a=b or m=0.
(2) (aᵐ)÷(aⁿ)=aᵐ⁻ⁿ
(3) (aᵐ)ⁿ= aᵐⁿ
(4) (ab)ᵐ= (aᵐ)×(bᵐ)
(5)(a÷b)ᵐ= (aᵐ)÷(bᵐ)
(6) If m is a positive number, a⁻ᵐ=1÷(aᵐ). Here, a⁻ᵐ is called reciprocal of aᵐ.
(7) If m,n are integer, aᵐ/ⁿ means (aᵐ)ˡ/ⁿ ; i.e., n-th root of aᵐ.
(8) If m=0, a⁰ is meaningless, a⁰=1.
(9) If a,m,n real and aᵐ=aⁿ then, m=n, where, a not equal to 0,1,-1.
(10) If a, b, m are real , and aᵐ= bᵐ then, either a=b or m=0.
Some examples:
(1) calculate, (2⁵)×(2⁻³) =?
Ans: we have, (2⁵)×(2⁻³) = 2⁵⁻³ = 2² = 4.
(2) calculate, (8²)÷ (2³) =?
Ans: we have, 8²= (2³)² = 2⁶.
Now,(8²)÷(2³) =(2⁶)÷(2³) = 2³=8.
(3) simplify,( 2⁵)× (5⁵)=?
Ans: we have, (2⁵)×(5⁵) = (2×5)⁵ = 10⁵.
(4) simplify, (9⁴)÷ (3⁴)=?
Ans: We have, (9⁴)÷(3⁴)= (9÷3)⁴ =3⁴.
(5) calculate, {(⁵√8)⁵/²} ×{(16)⁻³/⁸ }=?
Ans: we have, (⁵√8)⁵/² =(8)¹/² =(2³)¹/²=2³/².
Also, (16)⁻³/⁸ =(2⁴)⁻³/⁸ = 2⁻³/².
so,{(⁵√8)⁵/²} ×{(16)⁻³/⁸ }=2³/² × 2⁻³/² =2⁰=1.
(6) Arrange the following numbers in increasing order: 2⁶³ , 3⁴⁵ , 5²⁷ , 6¹⁸ .
Here, 2⁶³ = (2⁷)⁹ = (128)⁹ ;
3⁴⁵ =(3⁵)⁹ = (243)⁹ ;
5²⁷ =(5³)⁹ = (125)⁹ ;
6¹⁸ = (6²)⁹ = (36)⁹ ;
Since, 36<125<128<243
so, 6¹⁸<5²⁷<2⁶³<3⁴⁵.
Therefore, the increasing order is :
6¹⁸, 5²⁷, 2⁶³ ,3⁴⁵.
(5) calculate, {(⁵√8)⁵/²} ×{(16)⁻³/⁸ }=?
Ans: we have, (⁵√8)⁵/² =(8)¹/² =(2³)¹/²=2³/².
Also, (16)⁻³/⁸ =(2⁴)⁻³/⁸ = 2⁻³/².
so,{(⁵√8)⁵/²} ×{(16)⁻³/⁸ }=2³/² × 2⁻³/² =2⁰=1.
(6) Arrange the following numbers in increasing order: 2⁶³ , 3⁴⁵ , 5²⁷ , 6¹⁸ .
Here, 2⁶³ = (2⁷)⁹ = (128)⁹ ;
3⁴⁵ =(3⁵)⁹ = (243)⁹ ;
5²⁷ =(5³)⁹ = (125)⁹ ;
6¹⁸ = (6²)⁹ = (36)⁹ ;
Since, 36<125<128<243
so, 6¹⁸<5²⁷<2⁶³<3⁴⁵.
Therefore, the increasing order is :
6¹⁸, 5²⁷, 2⁶³ ,3⁴⁵.
If you find out any incorrect information or know anything more about this , please write it in the comment section!
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